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A bomb of mass 3.0 kg explodes in air in...

A bomb of mass `3.0 kg` explodes in air into two pieces of masses `2.0 kg` and `1.0 kg`. The smaller mass goes at a speed of `80 m//s`. The total energy imparted to the two fragments is :

A

1.07kJ

B

2014kJ

C

2.4kJ

D

4.8kJ

Text Solution

Verified by Experts

The correct Answer is:
D
Total linear momentum before explosion
= Total linear momentum after explosion
`:. Mu = m_(1) v_(1) +m_(2)v_(2)`
`:.3xx0=2xxv_(1) +1xx80`
`:. 2v_(1) = - 80 :. V_(1) = - 40 m//s`
This is the velocity of the bigger pieces
`:.` Total energy of the two pieces
`=1/2 xx2xx(-40)^(2)+1/2xx1xx(80)^(2)`
`=1600+3200=4800J`
`:.E= 4.8 xx10^(3) J = 4.8 KJ`
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