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The dimensional equaltion of torque is...

The dimensional equaltion of torque is

A

`[tau[=[L^(1)M^(1)T^(-2)]`

B

`[tau]=[L^(2)M^(1)T^(-2)]`

C

`[tau]=[L^(2)M^(2)T^(2)]`

D

`[tau]=[L^(2)M^(1)T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
B
`[tau] = [F xxd] = [ L ^(1) M^(1) T^(-2)L^(1)] = [ L^(2) M^(1)T^(-2)]`
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