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Two masses m(1) = 5 kg and m(2) = 4.8...

Two masses `m_(1) = 5 kg ` and `m_(2) = 4.8 kg ` tied to a string are hanging over a light friction less pulley. What is the acceleration of the massess when the system is free to move ?

A

`9.8 m//s^(2)`

B

`0.2m//s^(2)`

C

`4.8 m//s^(2)`

D

`5 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
The acceleration of the system is give by
` therefore a = ((m_(1) - m_(2))/(m_(1) + m_(2)))g = ((5-4.8)/(9.8)) xx 9.8`
` = (0.2)/(9.8) xx 9.8 = 0.2 m//s^(2)`
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