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If : cot theta + cot((pi)/4 + theta) = 2...

If `: cot theta + cot((pi)/4 + theta) = 2`, then : `theta` =

A

`2n pi +- pi/6`

B

`2 npi +- (pi)/3`

C

`npi +- (pi)/3`

D

`npi +- pi/6`

Text Solution

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The correct Answer is:
D
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