Home
Class 12
MATHS
sin^(-1)[sqrt(x^(2)-x^(3))- sqrt(x-x^(3)...

`sin^(-1)[sqrt(x^(2)-x^(3))- sqrt(x-x^(3))]=`

A

`sin^(-1)x + sin^(-1) sqrt(x)`

B

`sin^(-1)s - sin^(-1) sqrt(x)`

C

`sin^(-1)sqrt(x) - sin^(-1)x`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC FUNCTIONS

    MARVEL PUBLICATION|Exercise MASTERING THE BEST - ALL TOPICS|128 Videos
  • TRIGONOMETRIC FUNCTIONS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP: CHAPTER 3-3.1|10 Videos
  • TRIGONOMETRIC FUNCTIONS

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS - PART - B : MASTERING THE BEST|58 Videos
  • THREE DIMENSIONAL GEOMETRY

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS|39 Videos
  • VECTORS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|20 Videos

Similar Questions

Explore conceptually related problems

If y=(x sin^(-1)x)/(sqrt(1-x^(2)))+log sqrt(1-x^(2)), then prove that (dy)/(dx)=(sin^(-1)x)/((1-x^(2))^((3)/(2)))

The sum of solutions of the equation 2 sin^(-1) sqrt(x^(2)+x+1)+cos^(-1) sqrt(x^(2)+x)=(3pi)/(2) is :

If x in[-1/2,1] then sin^(-1)(sqrt(3)/(2)x-1/2sqrt(1-x^(2)))

If int(2x-sqrt(sin^(-1)x))/(sqrt(1-x^(2)))dx=C-2sqrt(1-x^(2))-(2)/(3)sqrt(f(x)) then f(x) is equal to

If sin^(-1)x_(i)in[0,1]AA i=1,2,3,....28 then find the maximum value of sqrt(sin^(-1)x_(1))sqrt(cos^(-1)x_(2))+sqrt(sin^(-1)x_(2))sqrt(sin^(-1)x_(3))+sqrt(sin^(-1)x_(3))sqrt(cos^(-1)x_(4))+...+sqrt(sin^(-1)x_(28))sqrt(cos^(-1)x_(1))

The velue of lim_(x rarr0)(sin(3sqrt(x))ln(1+3x))/((tan^(-1)sqrt(x))^(2)(e^(5(3sqrt(x)))-1)) is equal to

int sqrt((x)/(1-x))dx is equal to sin^(-1)sqrt(x)+C(b)sin^(-1){sqrt(x)-sqrt(x(1-x))}+C(c)sin^(-1){sqrt(x(1-x)}+C(d))sin^(-1)sqrt(x)-sqrt(x(1-x))+C

lim_(x rarr0)(sin^(3)(sqrt(x))log(1+3x))/((tan^(-1)sqrt(x))^(2)(e^(5sqrt(x))-1)x)=

lim_(x rarr oo)((sqrt(x^(2)+5)-sqrt(x^(2)-3))/(sqrt(x^(2)+3)-sqrt(x^(2)+1)))

The number of the solutions of the equation 2 sin^(-1) sqrt(x^(2) + x + 1) + cos^(-1) sqrt(x^(2) + x) = (3pi)/(2) is