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If tan^(-1)a + tan^(-1)b + tan^(-1)c= si...

If `tan^(-1)a + tan^(-1)b + tan^(-1)c= sin^(-1)1`, then

A

a+b+c=1

B

a+b+c=abc

C

abc=1

D

ab + bc + ca=1

Text Solution

Verified by Experts

The correct Answer is:
D
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