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If x in [0,2pi] and |sec x+ tan x|=|sec ...

If `x in [0,2pi]` and `|sec x+ tan x|=|sec x|+|tan x|`, then x lies in the interval

A

`[0,pi]`

B

`[0, pi/2) cup (pi/2, pi]`

C

`[0,p(3pi)/2) cup ((3pi)/2, 2pi]`

D

`(pi, 2pi)`

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The correct Answer is:
B
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