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If, in a triangleABC, (a+b+c)(b+c-a)=kbc...

If, in a `triangleABC, (a+b+c)(b+c-a)=kbc`, then k lies in the interval

A

(0,1)

B

(0,2)

C

(0,3)

D

(0,4)

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The correct Answer is:
D
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