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If y= sin^(2)theta + cosec^(2)theta, th...

If `y= sin^(2)theta + cosec^(2)theta, theta ne 0`, then

A

y=0

B

`y le 2`

C

`y ge -2`

D

`y ge 2`

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The correct Answer is:
To solve the problem where \( y = \sin^2 \theta + \csc^2 \theta \) and \( \theta \neq 0 \), we will follow these steps: ### Step-by-Step Solution: 1. **Start with the given expression:** \[ y = \sin^2 \theta + \csc^2 \theta \] 2. **Recall the identity for cosecant:** \[ \csc \theta = \frac{1}{\sin \theta} \] Therefore, we can express \( \csc^2 \theta \) as: \[ \csc^2 \theta = \frac{1}{\sin^2 \theta} \] 3. **Substitute \( \csc^2 \theta \) into the expression for \( y \):** \[ y = \sin^2 \theta + \frac{1}{\sin^2 \theta} \] 4. **Let \( x = \sin^2 \theta \). Then we can rewrite \( y \) as:** \[ y = x + \frac{1}{x} \] where \( x > 0 \) since \( \sin^2 \theta \) is always positive for \( \theta \neq 0 \). 5. **To find the minimum value of \( y \), we can use the AM-GM inequality:** \[ x + \frac{1}{x} \geq 2 \] This inequality holds for all \( x > 0 \). 6. **Equality holds when \( x = 1 \) (or \( \sin^2 \theta = 1 \), which occurs when \( \theta = \frac{\pi}{2} + n\pi \) for any integer \( n \)).** 7. **Thus, the minimum value of \( y \) is:** \[ y \geq 2 \] 8. **Conclusion:** The minimum value of \( y \) is 2, and it can be expressed as: \[ y \geq 2 \] ### Final Answer: \[ y \geq 2 \]
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