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If, in triangleABC, (cos A)/a =(cos B)/b...

If, in `triangleABC, (cos A)/a =(cos B)/b =(cos C)/c` and side a=2, then the area of the triangle is

A

1

B

2

C

`(sqrt(3))//2`

D

`sqrt(3)`

Text Solution

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The correct Answer is:
A, B, C, D
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