The magnetic field at a point on the magnetic equator is found to be `3.1 xx 10^(-5) T`. Taking the earth's radius to be 6400 km, calculate the magneitc moment of the assumed dipole at the earth's centre.

The magnetic field at a point on the magnetic equator is found to be 3*1xx10^-5T . Taking the earth's radius to be 6400km , calculate the magnetic moment of the assumed dipole at the earth's centre.

The magnetic field at a point on magnetic equator is 3*1xx10^-5T . If radius of earth is taken as 6400km , what is magnetic moment of the assumed dipole at the centre of earth?

The Earth's magnetic field at some place on magnetic equator of Earth is 0.5 xx 10^(-4)T. Consider the radius of Earth at that place as 6400 km. Then, magnetic dipole moment of the Earth is .... Am^(2) (mu=4pixx 10^(-7)TmA^(-1))

The magnetic field at a point, 10cm away from a magnetic dipole, is found to be 2.0 xx 10^(-4) T . Find the magnetic moment of the dipole if the point is (a) in end on position of the dipole and (b) in broadside-on position of the dipole.

The magnitude of earth magnetic field at magnetic equator is 2.8 xx 10^(-5) T . Find magnitude of earth's magnetic field near geomagnetic poles .

The magnetic field of earth at the equator is approximately 4xx10^(-5)T . The radius of earth is 6.4xx10^(6)m . Then the dipole moment (in A-m^(2) ) of the earth will be nearly of the order of

The magnetic field of earth at the equator is approximately 4 x× 10^(-5) T. The radius of earth is 6.4 x× 10^(6) m. Then the dipole moment of the earth will be nearly of the order of:

At a point above the surface of the earth, the gravitational potential is -5.12 xx 10^(7) J/kg and the acceleration due to gravity is 6.4 m//s^(2) . Assuming the mean radius of the earth to be 6400 km, calculate the height of the point above the earth's surface.

If the earth's magnetic field has a magnitude 3.4 xx 10^(-5) T at the magnetic equator of the earth, what would be its value at the earth's goemagnetic poles?