A tangent galvanometer has a cooil of 22 turns and mean radius 0.1 m. Find the reduction factor at a place , where `B_(H)=0.3xx10^(-4)T`.

A tangent galvanometer has a coil of 50 turns and a radius of 20 cm The horizontal component of the earth's magnetic field is B_(H)=3 xx 10^(-5)T . Find the current (in ampere) which gives a deflection of 45^(circ) . (Take pi=3 )

A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth's magnetic field is 3xx10^(-5)T . The current required to producea defection of 45^(@) in it, is

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is B_H = 3 xx 10^(-5) T . Find the current which gives a diflection of 45^) .

A tangent galvanometer ha s60 turns of wire of mean diameter 20 cm . Find the reduction factor of the tangent galvanometer at a place where the horizontal component of earth's magnetic field 0.32 xx 10^(-4) T .

Calculate the current through a tangent galvanometer whose cells has 50 turns and a mean diameter of 22 cm when the needle is deflected through 30^(@) at a place where H=30 Am^(-1)

The coil of a tangent galvanometer has 50 turns of mean diameter 20 cm. Find the current required to produce a deflection of 30^(@) . Given B_(H) =0.3 G.

The radius of the coil of a Tangent galvanometer, which has 10 turns, is 0.1 m. The current required to produce a deflection of 60^(@) (B_(H)=4xx10^(-5)T) is

A tangent galvanometer has a coil with 50 turns and radius equal to 4 cm . A current of 0.1 A is passing through it. The plane of the coil is set parallel to the earth's magnetic meridian. If the value of the earth's horizontal component of the magnetic field is 7xx10^(-5) Tesla and mu_(0)=4pixx10^(-7)Weber//ampxxm then the deflection in the galvanometer needle will be