Home
Class 12
PHYSICS
A circular of radius 0.157 m has turns. ...

A circular of radius 0.157 m has turns. It is placed such that its axis is in magnetic meridian. A dip needle is supported at the centre of the coil with its axis of rotation horizontal, and in the plane of the coil. The angle of dip is `30^(@)` when a current flows through the coil. The angle of dip becomes `60^(@)` on reversing the current. Find the current in the coil assuming that the magnetic field due to the coil is smaller than the horizontal component of earth's magnetic field, `H =3xx10^(-5) T`.

Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    SL ARORA|Exercise Based on Coulomb s law and dipole moment of a magnet|5 Videos

  • MAGNETISM

    SL ARORA|Exercise Based on Torque and potential energy of dipole in magnetic field|14 Videos

  • MAGNETISM

    SL ARORA|Exercise Based on (i) Earth s Magnetism (ii) magnetic field of a bar magnet|60 Videos

  • MAGNETIC EFFECTS OF CURRENT

    SL ARORA|Exercise TYPE C|4 Videos

  • OPTICAL INSTRUMENTS

    SL ARORA|Exercise Problems for self practice|35 Videos

Similar Questions

Explore conceptually related problems

A dip circle lies initially in the magnetic meridian. If it is now rotated through angle theta in the horizontal plane, then tangent of the angle of dip is changed in the ratio:

A circular coil of radius 20 cm and 20 turns of wire is mounted vertically with its plane in magnetic meridian.A small magnetic needle (free to rotate about vertical axis) is placed at the center of the coil.It is deflected through 45^(@) when a current is passed through the coil and in equilbrium (Horizontal component of earth's field is 0.34 xx 10^(-4) T ).The current in coil is:

A straight conductor is placed along the axis of a circular coil perpendicular to the plane of the coil. Then electric current is passed through both,

A neutral point is obtained at the centre of a vertical circular coil carrying current. The angle between the plane of the coil and the magnetic meridian is

A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20 cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30^(@) . Find the horizontal component of earth's magnetic field

A compass needle free to turn in a horizontal plane is placed at the centre of a circular coil of 30turns and radius 12cm. The coil is in a vertical plane malting an angle of 45^(@) with the magnetic meridian when the current in the coil is 0.35A, the needle points west to east. Determine the horizontal component of earth's magnetic field at the location.

A circular coil 'A' has a radius R and the current flowing through it is I.Another circular coil 'B' has a radius 2R and if 2I is the current flowing through it then the magnetic fields at the centre of the circular coil are in the ratio of

A circular coil 'A' has a radius R and the current flowing through it is I.Another circular coil 'B' has a radius 2R and if 21is the current flowing through it then the magnetic fields at the centre of the circular coil are in the ratio of

A circular coil 'A' has a radius R and the current flowing through it is I.Another circular coil 'B' has a radius 2R and if 21is the current flowing through it then the magnetic fields at the centre of the circular coil are in the ratio of

If a dip needle is suspended at an angle 30° to the magnetic meridian, it makes an angle of 45^@ with the horizontal. The real dip is