Home
Class 12
PHYSICS
A magnet makes 12 oscillations per minut...

A magnet makes 12 oscillations per minutes at a place a where the horizontal component of earth's field is `3.2 xx 10^(-3)T` . It is found to require 4 seconds per oscillation at another place B. Calculate the vertical component of earth's field at place B, if dip at B is `45^(@)`.

Text Solution

Verified by Experts

The correct Answer is:
`5 xx 10^(-5) T`
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    SL ARORA|Exercise Based on Torque and potential energy of dipole in magnetic field|14 Videos

  • MAGNETIC EFFECTS OF CURRENT

    SL ARORA|Exercise TYPE C|4 Videos

  • OPTICAL INSTRUMENTS

    SL ARORA|Exercise Problems for self practice|35 Videos

Similar Questions

Explore conceptually related problems

The value of horizontal component of earth's magnetic field at a place is -.35xx10^(-4)T . If the angle of dip is 60^(@) , the value of vertical component of earth's magnetic field is about:

The horizontal component of earth's magnetic field at a place is 0*4xx10^-4T . If angle of dip 45^@ , what are the values of vertical component and total field strength of earth's field?

At a place the earth's horizontal component of magnetic field is 0.36xx10^(-4) "Weber"//m^(2) . If the angle of dip at that place is 60^(@) , then the vertical component of earth's field at that place in "Weber"//m^(2) will be approxmately

At a certain place , the horizontal component of earth's magnetic field is (1)/(sqrt3) times of its vertical component . The angle of dip at that place is

The angle of dip at a place where horizontal and vertical components of earth magnetic field are same, is

SL ARORA-MAGNETISM-Based on (i) Earth s Magnetism (ii) magnetic field of a bar magnet
  1. A circuit coil of radius 20 cm and 20 turns of wire is mounted vertica...

    Text Solution

    |

  2. Two tangent galvanometer P and Q are connected in series and a curre...

    Text Solution

    |

  3. A magnetic needle of dipole moment 0.067 JT^(-1) oscillates with a per...

    Text Solution

    |

  4. A small bar magnet of magnetic moment 9.75 xx 10^(-3) J T^(-1) is susp...

    Text Solution

    |

  5. A magnetic needle pivoted through it centre of mass and free to rotat...

    Text Solution

    |

  6. A magnet suspended so as to swing horizontally makes 50 vibrations per...

    Text Solution

    |

  7. A magnet is suspended in such a way that it oscillates in the horizont...

    Text Solution

    |

  8. A magnet makes 12 oscillations per minutes at a place a where the hori...

    Text Solution

    |

  9. A magnet makes 10 oscilllations per minute at a place where the angle ...

    Text Solution

    |

  10. The combination of two bar magnets makes 10 oscillations per second in...

    Text Solution

    |

  11. A small magnet A makes 10 vibrations in 90 seconds in earth's field. W...

    Text Solution

    |

  12. A thin rod 30 cm long is uniformly magnetised and its period of oscill...

    Text Solution

    |

  13. A short magnet oscillates in a vibration magnetometer with a time per...

    Text Solution

    |

  14. A bar magnet made of steel has a magnetic moment of 2.5 A m^2 and mass...

    Text Solution

    |

  15. Find the percent increase in the magnetic field B when the space withi...

    Text Solution

    |

  16. The susceptibility of magnesium at 300 K is 1.2 xx 10^(-5). At what te...

    Text Solution

    |

  17. An iron rod 0.2 m long, 10 mm in diameter and of permeability 1000 is ...

    Text Solution

    |

  18. An iron ring of mean circumferential length 30 cm and cross-section 1 ...

    Text Solution

    |

  19. A material core has 10 turns per cm of wire wound uniformly upon it wh...

    Text Solution

    |

  20. An iron ring having 500 turns of wire and mean diameter of 12 cm carri...

    Text Solution

    |