A ball throuwn vertically upwards with a speed of `19.6ms^(-1)` from the top of a tower returns to the earth in 6s. Find the height of the tower.

A ball thrown vertically upwards with a speed of 19.6 ms^(-1) from the top of a tower returns to earth in 6 s . Calculate the height of the tower.

A stone is thrown vertically upwards with an initial speed u from the top of a tower, reaches the ground with a speed 3 u . The height of the tower is :

A ball is thrown vertically upwards with a speed of 10 m//s from the top of a tower 200 m height and another is thrown vertically downwards with the same speed simultaneously. The time difference between them on reaching the ground is (g=10 m//s^(2))

A stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u. The height of the tower is

A ball is thrown upwards with speed v from the top of a tower and it reaches the ground with speed 3v .The height of the tower is

A ball is thrown upwards with speed ‘v’ from the top of a tower and it reaches the ground with a speed 3v, then the height of the tower is

A particle is dropped from the top of a tower. It covers 40 m in last 2s. Find the height of the tower.

A ball is projected vertically upwards with a velocity of 25ms^(-1) from the bottom of a tower. A boy who is standing at the top of a tower is unable to catch the ball when it passes him in the upward direction. But the ball again reaches him after 3 sec when it is falling. Now the boy catches it then the height of the tower is (g=10ms^(-2))