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A particle is projected from gound At a height of 0.4 m from the ground, the velocity of a projective in vector form is `vecv=(6hati+2hatj)m//s` (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is `(g=10m//s^(2))`

A

`45^(@)`

B

`60^(@)`

C

`30^(@)`

D

`tan^(-1)(3//4)`

Text Solution

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The correct Answer is:
C
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