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Velocity of a projectile at height 15 m ...

Velocity of a projectile at height `15 m` from ground is `v=(20hati+10hatj)m//s`. Here `hati` is in horizontal direction and `hatj` is vertically upwards. Then
Speed with which particle is projected from ground is……… m/s

A

30

B

`20sqrt(2)`

C

`sqrt(20)`

D

`3sqrt(40)`

Text Solution

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The correct Answer is:
B
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Assertion At height 20 m from ground , velocity of a projectile is v = (20 hati + 10 hatj) ms^(-1) . Here, hati is horizontal and hatj is vertical. Then, the particle is at the same height after 4s. Reason Maximum height of particle from ground is 40m (take, g = 10 ms^(-2))

Knowledge Check

  • Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Angle of projectile with ground is

    A
    `45^(@)`
    B
    `30^(@)`
    C
    `37^(@)`
    D
    `60^(@)`

  • Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Maximum height from a ground is …….. m

    A
    30
    B
    60
    C
    40
    D
    20

  • Velocity of a projectile at height 15 m from ground is v=(20hati+10hatj)m//s . Here hati is in horizontal direction and hatj is vertically upwards. Then Horizontal range of the ground is ………… m

    A
    60
    B
    50
    C
    80
    D
    70

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