Home
Class 11
PHYSICS
A particle of mass 1 kg is projected at ...

A particle of mass 1 kg is projected at an angle of `30^(@)` with horizontal with velocity v = 40 m/s . The change in linear momentum of the particle after time t = 1 s will be (g = 10 `m// s^(2)`)

A

7.5 kg- m/s

B

15 kg - m/s

C

10 kg-m/s

D

20 kg-m/s

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS, IMPULSE AND MOMENTUM

    DC PANDEY|Exercise Only one option is correct for JEE Advanced|55 Videos

  • CENTRE OF MASS, IMPULSE AND MOMENTUM

    DC PANDEY|Exercise More a than one option is Correct|1 Videos

  • CENTRE OF MASS

    DC PANDEY|Exercise Medical entrances gallery|27 Videos

  • CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION

    DC PANDEY|Exercise Level 2 Subjective|21 Videos

Similar Questions

Explore conceptually related problems

A particle is projected at an angle 60^(@) with the horizontal with a speed 10m//s . Then, latus rectum is (Take g=10m//s^(2) )

A particle of mass m is projected with a speed u at an angle theta with the horizontal. Find angular momentum of particle after time t about point of projection.

A particle is projected from the ground at an angle of 60^(@) with horizontal at speed u = 20 m//s. The radius of curvature of the path of the particle, when its velocity. makes an angle of 30^(@) with horizontal is : (g=10 m//s^(2)

A particle is moving with velocity v=4t^(3)+3 t^(2)-1 m//s . The displacement of particle in time t=1 s to t=2 s will be

A particle is projected at an angle 60^@ with horizontal with a speed v = 20 m//s . Taking g = 10m//s^2 . Find the time after which the speed of the particle remains half of its initial speed.

An object of mass 10 kg is projected from ground with speed 40 m/s at an angle 60^(@) with horizontal the rate of change of momentum of object one second after projection in SI unit is [ Take g = 9.8 m/ s^(2) ]

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

A particle is projected at an angle of 30^(@)w.r.t. horizontal with speed 20m//s:( use g=10m//s^(2)) (i) Find the position vector of the particle after 1s . (ii) Find the angle between velocity vector and position vector at t=1s .

DC PANDEY-CENTRE OF MASS, IMPULSE AND MOMENTUM-Comprehension type questions
  1. A particle of mass 1 kg is projected at an angle of 30^(@) with horizo...

    Text Solution

    |

  2. Comprehension # 1 If net force on a system in a particular direction...

    Text Solution

    |

  3. Comprehension # 1 If net force on a system in a particular direction...

    Text Solution

    |

  4. Comprehension # 1 If net force on a system in a particular direction...

    Text Solution

    |

  5. Comprehension # 1 If net force on a system in a particular direction...

    Text Solution

    |

  6. Comprehension # 2 When two bodies collide normally they exert equal ...

    Text Solution

    |

  7. Comprehension # 2 When two bodies collide normally they exert equal ...

    Text Solution

    |

  8. Two identiacal masses are as shown in figure. One is thrown upwards wi...

    Text Solution

    |

  9. Two identiacal masses are as shown in figure. One is thrown upwards wi...

    Text Solution

    |

  10. Two identiacal masses are as shown in figure. One is thrown upwards wi...

    Text Solution

    |

  11. Comprehension # 4 When the mass of a system is variable, a thrust fo...

    Text Solution

    |

  12. Comprehension # 4 When the mass of a system is variable, a thrust fo...

    Text Solution

    |

  13. Comprehension # 4 When the mass of a system is variable, a thrust fo...

    Text Solution

    |

  14. Acceleration of two identical particles moving in a straight line are ...

    Text Solution

    |

  15. Acceleration of two identical particles moving in a straight line are ...

    Text Solution

    |

  16. Comprehension # 5 One particle of mass 1 kg is moving along positive...

    Text Solution

    |