In a ptentiometer experiment it is found that no current passes through the galvanometer when the terminals of a cell are connected across 509 cm of the potentiometer wire. When the cell is cnnected across 490 cm of the wire Find the internal resistance of the cell.

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

It is observed in a potentiometer experiment that no current passes through the galvanometer, when the terminals of the potentiometer, wire. On shunting the cell by a 2Omega resistance, the balancing length is reduced to half. The internal resistance of the cell is:-

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

The emf of a daniel cell is 1.08 V. When the terminals of the cells are connected to a ressitance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then the internal resistance of the cell is

A cell of emf 'E' is connected across a resistance R.The potential difference between the terminals of the cell is found to be "V" .The internal resistance of the cell must be:

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?