A 5- Wire potentiometer is connected to a storage cell of steady emf 2 V and 1 `Omega` resistance. A primary cell is balanced against 305 m of it.What resistance will be required in series with the storage cell to push the null point to the center of the last wire, i.e 4.5 m? (The wire has 3 `Omega` resistance per metre)

A 5 m potentiometer wire having 3 Omega resistance per meter is connected to a storage cell of steady emf 2 V and internal resistance 1 Omega . A primary cell is balanced against 3.5 m of it. When a resistance of 32//n Omega is put in series with the storage cell, the null point shifts to the centre of the last wire, i.e., 4.5 m . What is 'n'?

An accumulator with a steady emf of 2 V is connected across a potentiometer wire at 6.732 m If a resistance of 2.5 Omega is put in series with the wire find the new position of the null point.

A wire of length 100 cm is connected to a cell of emf 2 V and negligible internal resistance. The resistance of the wire is 3 Omega . The additional resistance required to produce a potential drop of 1 milli volt per cm is

A metre bridge wire of resistance 3 Omega is connected to a cell of emf 2 V and internal rsistance 1 Omega Claculate the p.d cm of the wire What length of this wire will balace a fesh dry cell of emf 1.5 V?

A potentiometer wire has resistance of per unit length of 0.1Omega//m . A cell of e.m.f. 1.5V balances against 300cm length of the wire. Find the current in the potentiometer wire.

The wire of potentiometer has resistance 4Omega and length Im. It is connected to a cell of EMF 2V and internal resistance 1Omega . Ifa cell ofEMF 1.2V is balanced byit, the balancing length will be:

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.