The equation of an alternating emf is `epsi =50 sin 100 pi t` Calculate (i) the perk volue of the emf of the emf (ii) the mean volue of the emf (iii) rms volue of the emf (iv) What Is the interval at which at which it attains maximum value?

The equation of an alternating currect is i=2 sin 200 pi t . Calculate (i) the prak volue of the currect (ii) the mean volue of the currect (iii) virtual current.

An alternating emf is represented by E = 100 si n ( 120 pi t + pi //4) volt. Calculate (i) Average or mean value of emf (ii) RMS value of emf (iii) Frequency of alternating emf (iv) the shortest time interval after start at which emf is zero.

An alternating emf is represented by E = 100 si n ( 120 pi t + pi //4) volt. Calculate (i) Average or mean value of emf (ii) RMS value of emf (iii) Frequency of alternating emf (iv) the shortest time interval after start at which emf is zero.

The value of alternating e.m.f. is e = 500 sin 100pit , then the frequency of this potential in Hz is –

The instantaneous emf an a.c. source is given by epsi=300 sin 314 t . What is the rms value of the emf?

When an alternating emf, e=300 sin 100pit volt is applied across a bulb, the peak value of current is found to be 2 A. the average power is

If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 Omega and L = 800 mH, the peak value of current will be in ampere :

An alternating emf, e=300 sin100 pit volt, is applied to a pure resistance of 100 Omega . The rms current through the circuit is

If the peak value of an alternating emf is 15V, what is its mean value over half cycle?

An alternating e.m.f. is given by E=10 cos omega t . If the frequency is 50 Hz, then at time t=(1/600)s the instantaneous value of e.m.f. is