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A source of frequency 10kHz when vibrted...

A source of frequency 10kHz when vibrted over than mouth of a closed organ is in unison at 300K. The beats produced when temperature rises by 1K

A

30Hz

B

13.33Hz

C

16.67Hz

D

40Hz

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The correct Answer is:
To solve the problem step by step, we will follow the concepts of wave motion and the relationship between frequency, temperature, and the speed of sound. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Frequency of the source (f) = 10 kHz = 10,000 Hz - Initial temperature (T1) = 300 K - Change in temperature (ΔT) = 1 K 2. **Understand the Relationship between Frequency and Temperature:** - The frequency of sound in a closed organ pipe is directly proportional to the square root of the temperature: \[ f \propto \sqrt{T} \] - Therefore, we can express the relationship as: \[ \frac{f'}{f} = \sqrt{\frac{T'}{T}} \] - Where \(f'\) is the new frequency at temperature \(T'\) and \(f\) is the frequency at temperature \(T\). 3. **Calculate the New Temperature:** - The new temperature after the increase is: \[ T' = T1 + \Delta T = 300 K + 1 K = 301 K \] 4. **Calculate the New Frequency (f'):** - Using the ratio of frequencies: \[ \frac{f'}{10,000} = \sqrt{\frac{301}{300}} \] - Squaring both sides gives: \[ f'^2 = 10,000^2 \cdot \frac{301}{300} \] - Taking the square root: \[ f' = 10,000 \cdot \sqrt{\frac{301}{300}} \] 5. **Approximate the Square Root:** - For small changes, we can use the binomial approximation: \[ \sqrt{1 + x} \approx 1 + \frac{x}{2} \text{ for small } x \] - Here, \(x = \frac{1}{300}\): \[ \sqrt{\frac{301}{300}} \approx 1 + \frac{1}{2 \cdot 300} = 1 + \frac{1}{600} \] - Therefore: \[ f' \approx 10,000 \left(1 + \frac{1}{600}\right) = 10,000 + \frac{10,000}{600} = 10,000 + 16.67 \approx 10,016.67 \text{ Hz} \] 6. **Calculate the Beat Frequency:** - The beat frequency (Δf) is given by the difference between the new frequency and the original frequency: \[ Δf = f' - f = 10,016.67 - 10,000 = 16.67 \text{ Hz} \] ### Final Answer: The beats produced when the temperature rises by 1 K is approximately **16.67 Hz**.
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