Home
Class 11
PHYSICS
In each of the four situations of column...

In each of the four situations of column-I , a stretched string or an organ pipe is given along with the required data. In case of strings the tension in string is T=102.4 N and the mass per unit length of string is 1g/m. Speed of sound in air is 320 m/s. Neglect end corrections.The frequencies of resonance are given in column-II.Match each situation in column-I with the possible resonance frequencies given in Column-II.

Text Solution

Verified by Experts

The correct Answer is:
(a)P,R (b)Q,S(c )P,R(d)Q,S
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    DC PANDEY|Exercise Integer Type Question|11 Videos

  • WAVE MOTION

    DC PANDEY|Exercise Comprehion Type Questions|19 Videos

  • VECTORS

    DC PANDEY|Exercise Medical enrances gallery|9 Videos

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos

Similar Questions

Explore conceptually related problems

In the situation shown, the tension in the string is 22N. What is m (in kg) ?

Which of the following is not the law of a stretched string ? ( n , l , T and m are frequency of vibration , length of vibrating string , tension in string and linear mass density , respectively .)

A narrow pipe of length 2m is closed at one end. The velocity of sound in air is 320 m/s. Neglecting end corrections , the air column in the pipe will resonate for sound of frequencies :

The frequency (f) of a stretched string depends upen the tension F (dimensions of form ) of the string and the mass per unit length mu of string .Derive the formula for frequency

A string of 7 m length has a mass of 0.035 kg. If tension in the string is 60.5 N, then speed of a wave on the string is :