Home
Class 11
PHYSICS
A particle is moving on a straight line....

A particle is moving on a straight line. Its velocity at time `t` is `(8-2t)m//s`. What is the total distance covered from `t=0` to `t=6s`?

A

`12m`

B

`16m`

C

`18m`

D

`20m`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS 1

    DC PANDEY|Exercise MCQ_TYPE|27 Videos

  • KINEMATICS 1

    DC PANDEY|Exercise COMPREHENSION_TYPE|19 Videos

  • KINEMATICS

    DC PANDEY|Exercise INTEGER_TYPE|11 Videos

  • LAWS OF MOTION

    DC PANDEY|Exercise Medical entrances gallery|39 Videos

Similar Questions

Explore conceptually related problems

The position versus time graph of a particle moving along a straight line is shown. What is the total distance travelled by the particle from t=0s to t=10s?

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle is moving in a straight line with initial velocity u and uniform acceleration f . If the sum of the distances travelled in t^(th) and (t + 1)^(th) seconds is 100 cm , then its velocity after t seconds, in cm//s , is.

A particle is moving in a straight line and its velocity varies with its displacement as v=sqrt(4+4s) m/s. Assume s=0 at t=0. find the displacement of the particle in metres at t=1s.

The equation of motion of a particle moving on circular path (radius 200 m) is given by s = 18 t + 3t2 – 2t3 where s is the total distance covered from straight point in metres at the end of t seconds. The maximum speed of the particle will be-

A particle is moving in a striaght line according as S=15t+6t^2-t^3 , then the time it will come to rest is

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

A partical is moving in a straight line such that ita velocity is given by v=t^(4)+3t^(2)+8 m//s . Find acceleration at time t=1 s .

The velocity v of a particle at any instant t moving in a straight line is given by v=s +1 where s meter is the distance travelled in t second what is the time taken by the particle to cover a distacne of 9m ?