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Velocity of a particle varies with time ...

Velocity of a particle varies with time as `v=athati+2ht^(2)hatj`. If the particle starts from point `(0,c)`, the trajectory of the particle is

A

`y=(bx^(3//2))/a+c`

B

`y=(4sqrt(2)b)/3(x/a)^(3//2)+c`

C

`y=(4sqrt(2)b)/3(x/a)^(3//2)-c`

D

`y=(bx^(3//2))/a-c`

Text Solution

Verified by Experts

The correct Answer is:
A
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