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Let epsi0 denote the dimensional formula...

Let `epsi_0` denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as `[M^(p)L^(q)T^(r)A^(s)]`. Find the value of `(p-q+r)/(s)`

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