In X-ray tube , when the accelerating vo...

In X-ray tube , when the accelerating voltage `V` is halved, the difference between the wavelength of `K_(alpha)` line and minimum wavelength of continuous X-ray spectrum

remains constant

becomes more than two times

becomes half

becomes less than two times

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What is the minimum wavelength of X–rays

In a Coolidge tube, the potential difference used to accelerate the electrons is increased from 24. 8 kV to 49.6 kV . As a result, the difference between the wavelength of K_(alpha) -line and minimum wavelength becomes two times. The initial wavelength of the K_(alpha) line is [Take (hc)/(e) = 12 .4 kV Å ]

When the voltage applied to an X-ray tube increased from V_(1)=15.5kV to V_(2)=31kV the wavelength interval between the K_(alpha) line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of 1.3 . If te atomic number of the element of the target is z. Then the value of (z)/(13) will be: (take hc=1240eVnm and R=1xx(10^(7))/(m))

An X-ray tube has nickel as target. The wavelength difference between the ka X-ray and the cut-off wavelength of continuous X-ray spectrum is 84 pm. Find the accelerating voltage applied in the X-ray tube. [Take hc = 12400 eV Å ]

In x-ray tube experiment accelerating voltage is given by 1.24 MV. Find cutoff wavelength.

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