Determine the impedance of a series LCR - circuit if the reactance of C and L are `250 Omega` and `220 Omega` respectively and R is `40 Omega`

A circuit contains R, L and C connected in series with an A. C. source. The values of the reactances for inductor and capacitor are 200Omega and 600Omega respectively and the impedance of the circuit is Z1 . What happens to the impedance of the same circuit if the values of the reactances are interchanged:-

In an A.C circuit the instantaneous values of current and voltage are I = 120 sin omega t ampare and E = 300 sin (omega t + pi//3) volt respectively. What will be the inductive reactance of series LCR circuit if the resistance and capacitve reactrance are 2 ohm and 1 ohm respectively?

If the impedance of an L-C R circuit is 40 Omega , then the admitance of the circuit will be

In a series LCR circuit, the total reactance is 4 Omega and resistance is 3 Omega . Its power factor is

Find capacitance in a series LCR circuit in order to get maximum power. ( X_L = 250 Omega and f = 50 Hz )

The resonant frequency of a series LCR circuit with L=2.0 H,C =32 muF and R=10 Omega is

A series RLC circuit is connected to an AC supply 220 V, 50 Hz. The value of R is 10 Omega . The value of capacitive reactance of capacitor and incuctive reactance of inductor are 15 Omega and 20 Omega respectively . Calculate the value of current in the circuit.

For an LCR series circuit with an aac source of angular frequency omega .

The current in series LCR circuit will be the maximum when omega is

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is