At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is `100 m^(3) s^(-1)`. If the turbine generator efficiency is 60%, estimate the electric power available from the plant `(g = 9.8 ms^(-2))`.

In Koyna hydroelectric power station, water stored at a height of 600 metre fall on the turbine blades and the water flow avilable is 100 m^(3)//s . The efficiency of the turbine generator is 50%. What is the power available from the power station? [g=10 m//s^(2)]

A hydroelectric power plant produces energy from flowing water.

In a hydroelectric power plant more electrical power can be generated if water falls a greater height because :

A crane lifts a mass of 100 kg to a height of 10 m in 20 s. The power of the crane is (Take g = 10 m s^(-2) )

A crane lifts a mass of 100 kg to a height of 10m in 20s . The power of the crane is (Take g = 10 ms^(-2))

Water enter in a turbine at a speed of 500 m/s and leaves at 400 m/s. If 2xx10^(3)kg//s of water flows and efficiency is 75% then output power is