The threshold frequency of a certain metal is `3.3xx10^(14)Hz`. If light of frequency `8.2xx10^(14)Hz` is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, `h=6.62xx10^(-34)Js`.

The threshold freqeuncy of a certain metal is 3.3xx10^(14)Hz . If light of frequency 8.2xx10^(4)Hz is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, h=6.62xx10^(-34)Js .

The threshold frequency for a certain metal is 3.3xx10^(14) Hz. If light of frequency 8.2xx10^(1) Hz (hertz) is incident on the metal , find the cut - off voltage for photoelectric emission . Given Planck's constant h = 6.625xx10^(-34) Js (joule second ) . Charge of electron e = 1.6 xx10^(-19) C (coulomb).

If light of frequency 8.2xx10^14 Hz is incident on the metal , cut-off voltage for photoelectric emission is 2.03 V.Find the threshold frequency . Given h= 6.63xx10^(-34) Js , e= 1.6xx10^(-19) C.

If light of frequency 8.2 xx 10^(14) Hz is incident on the metal , cut-off voltage for photoelectric emission is 2.03 V. Find the threshold frequency . Given h = 6.63 xx 10^(-34) Js , e = 1.6 xx 10^(-19) C .

The threshold frequency for a certain metal for photoelectric effect is 1.7x10^(15)Hz . When light of frequency 2.2xx10^(15)Hz is incident on the metal surface, the kinetic energy of the emitted photoelectrons is 3.3xx10^(-19)J . What is the value of the Planck's constant ?

The threshold frequency of a material is 2xx10^14 Hz. What is its work function in eV ?

A photon of frequency 5 xx 10^(14)Hz is incident on the surface of a metal. What is the energy of the incident photon in eV?