Home
Class 12
PHYSICS
In an experiment on photoelectric effect...

In an experiment on photoelectric effect, the slope of the cut off voltage versus frequency of incident light is found to be `4.12xx10^(-15)Vs`. Given `e=1.6xx10^(-19)C`, estimate the value of Planck's constant.

Promotional Banner

Topper's Solved these Questions

  • ELECTRONS AND PHOTONS

    SL ARORA|Exercise Problem Solution|19 Videos
  • ELECTRONS AND PHOTONS

    SL ARORA|Exercise TYPE A : Problem For Self Practice|21 Videos
  • ELECTROMAGNETIC WAVES

    SL ARORA|Exercise Problem for self-practice|21 Videos
  • ELECTROSTATIC FORCES, CHARGES AND FIELDS

    SL ARORA|Exercise Problems For Self Practice|1 Videos

Similar Questions

Explore conceptually related problems

In an experiment on the photoelectric effect , the slope of the cut - off voltage versus frequency of incident light is found to be 4.12xx10^(-15) V s . The value of Planck's constant is

Photons of frequencies 2.2xx10^(15) Hz and 4.6xx10^(15) Hz are incident on a metal surface. The corresponding stopping potentials were found to be 6.6V and 16.5V respectively. Given e=1.6xx10^(-19) c , the value of universal planck's constant is

Calculate the speed of the electron in the first Bohr orbit given that h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg and e=1.603xx10^(-19) C .

For photoelectric effect in sodium, fig. shows the plot of cut-off voltage versus frequency of the incident radiation. Caclculate: (i) the threshold frequency (ii) the work function for sodium. (Use h=6.6xx10^(-34)Js )

In a photoelectric experiment it was found that the stopping potential decreases from 1.85 V to 0.82 V as the wavelength of the incident light is varied from 300 nm to 400 nm. Calculate the value of the Planck constant from these data.

Electrons ejected from the surface of a metal, when light of certain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begains at a frequency 6xx10^(14)s^(-1) . The frequency of the incident light in s^(-1) is [h=6 x10^(-34) J-sec , charge on the electron = 1.6xx10^(-19)C ]

By how which would the stopping potential for a given photosensitive surface go up if the frequency of the incident radiations were to be increased from 4xx10^(15)Hz to 8xx10^(15)Hz ? Given, h=6.6xx10^(-34)Js , e=1.6xx10^(-19)C and c=3xx10^8ms^-1 .