Home
Class 12
PHYSICS
If photoelectrons are to be emitted from...

If photoelectrons are to be emitted from a potassium surface with a speed of `6 xx 10^(6)ms^(-1)`, what frequency of radiation must be used ? (Threshold frequency for potassium is `4.22 xx 10^(14) Hz, h = 6.6 xx 10^(-34) Js` and `m_(e) = 9.1 xx 10^(-31) kg`)

Promotional Banner

Topper's Solved these Questions

  • ELECTRONS AND PHOTONS

    SL ARORA|Exercise Problem Solution|19 Videos
  • ELECTRONS AND PHOTONS

    SL ARORA|Exercise TYPE A : Problem For Self Practice|21 Videos
  • ELECTROMAGNETIC WAVES

    SL ARORA|Exercise Problem for self-practice|21 Videos
  • ELECTROSTATIC FORCES, CHARGES AND FIELDS

    SL ARORA|Exercise Problems For Self Practice|1 Videos

Similar Questions

Explore conceptually related problems

The photoelectron of work function 3.1 eV is emitted with velocity 2.5 xx 10^(6) m/s . The frequency of incident radiation is

If wavelength of photon is 2.2 xx 10^(-11)m , h = 6.6 xx 10^(-34) Js , then momentum of photons is

The kinetic energy of an electron is 5 eV . Calculate the de - Broglie wavelength associated with it ( h = 6.6 xx 10^(-34) Js , m_(e) = 9.1 xx 10^(-31) kg)

Calculate the kinetic energy of the ejected electron when ultra-violet radiation of frequency 1.6 xx 10^(15) s^(-1) strikes the surface of potassium metal. Threshold frequency of potassium is 5 xx 10^(14) s^(-1) (h = 6.63 xx 10^(-34) Js) .

Light of frequency 7.21xx10^(14)Hz is incident on a metal surface. Electrons with a maximum speed of 6.0xx10^(5)ms^(-1) are ejected from the surface. What is the threshold frequency for photoemission of electrons? h=6.63xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg .

Energy of an quanta of frequency 10^(15) Hz and h = 6.6 xx 10^(-34) J - sec will be

If the speed of photoelectrons is 10^(6) ms^(-1) , what should be the frequency of the incident radiation on the potassium metal ? (Work function of potassium = 2.3 eV).