If the speed of photoelectrons is `10^(6) ms^(-1)`, what should be the frequency of the incident radiation on the potassium metal ? (Work function of potassium = 2.3 eV).

If the speed of photoelectrons is 10^(4) ms^(-1) , what should be the frequency of incident radiation on the potassium metal ? Work function of potassium = 2.3 eV.

if the speed of photoelectrons is 10^4 m/s, what should be the frequency of the incident radiation on a potassium metal ? Given : Work function of potassium =2.3 eV

The threshold frequency for certain metal is v_0 . When light of frequency 2v_0 is incident on it, the maximum velocity of photoelectrons is 4xx10^(6) ms^(-1) . If the frequency of incident radiation is increaed to 5v_0 , then the maximum velocity of photoelectrons will be

What is the energy of emitted photoelectrons is light of frequency 10^(16) Hz is incident on a sodium target ? Work function of sodium is = 2.5 eV.

The work function of a metal is 4 eV. What should be the wavelength of the incident radiation for the emission of photoelectrons of zero velocity ?

The work function of a metal is 3.4 eV. If the frequency of incident radiation is increased to twice, then the work function of the metal becomes.

Statement-1: Kinetic energy of photoelectrons increases with increases in the frequency of incident radiation Statement-2: The number of photoelectrons ejected increases with increases in intensity of incident radiation.