Home
Class 12
PHYSICS
In the circuit Fig. the value of beta is...

In the circuit Fig. the value of beta is 200. Find `I_(B), V_(CE), V_(BE)` and `V_(BC)`, when `I_(C)=2.5mA`. The transistor is in active, cut off or saturation state.

Text Solution

Verified by Experts

The correct Answer is:
NA
Promotional Banner

Topper's Solved these Questions

  • SOLIDS AND SEMICONDUCTOR DEVICES

    SL ARORA|Exercise PROBLEM_TYPE|9 Videos

  • RAY OPTICS

    SL ARORA|Exercise TYPE I|12 Videos

  • THERMOELECTRICITY

    SL ARORA|Exercise Problems for Self Practice|13 Videos

Similar Questions

Explore conceptually related problems

In the accompanying circuit (Fig. 5.9) the value of beta is 100 . Find I_(B),V_(CE),V_(CE) and V_(BC) , when I_(C) =1.5 mA . Is the transistor in active, cut-off or saturation state ?

In the common emitter circuit as shown in Fig, the value of the current gain is 100. Find I_(B),V_(CE),V_(BE),V_(BC) when I_(C)=1.5mA . The transistor is in active, cutoff or saturation state.

In the circuit shows in the figure, the input voltage V_(i) is 20 V, V_(BE)=0 and V_(CE)=0 . The values of l_(B), l_(C) and beta are given by

In the circuit shown in Fig. when the input voltage of the base resistance is 10V, V_(be) is zero and V_(ce) is also zero. Find the values of I_, I_ and beta .

In the circuit shown in the figure, the input voltage V_(i) is 20V, V_(BE)=0 and V_(CE) = 0 . The values of I_(B) , I_(C) and beta are given by

In the circuit shown in the figure, the input voltage V_(i) is 20V,V_(BE)=0 and V_(CE)=0 . The values of I_(B),I_(C) and beta are given by:

In the following common emitter circuit if beta=100, V_(CE)=7 V, V_(BE) =Negligible, R_(C)=2 kOmega then I_(B)=?

In the following common emitter circuit , if beta = 100 , V_(CE)=7 V , R(C)=2 kOmega and V_(BE) negligible , then I_B is