An `alpha`-particle after passing through a potential difference of `2 xx 10^(6) V` falls on a silver foil. The atomic number of silver is 47. Calculaye (i) the kinetic energy of the `alpha`-particle at the time of falling on the foil (ii) the kinetic energy of the `alpha`-particle at a distance of `5 xx 10^(-14)` m from the nucleus and (iii) the shortest distance from the nucleus of silver to which the `alpha`-particle reaches.