Express 1 joule in eV. Taking 1a.m.u. `=931 MeV`, calculate the mass of `._6C^12`.

Express 1 mg mass equivalent in eV

Assertion : 1 amu is equal to 931.48 MeV. Reason: 1 amu is equal to 1/12th the mass of C^12 atom.

Find the energy equivalent of one atomic mass unit, first in joule and then in MeV. Using this, express the mass defect of ._8O^(16) in Me V//c^2 . Given M_(p)=1.007825u and M_(n) =1.008665 u, m_("oxy")=15.99053 a.m.u. and Take 1 a.m.u=933.75MeV//c^2 .

Calculate the energy released in fusion reaction : 4._(1)^(1)Hto._(2)^(4)He+2._(+1)^(0)e Given : mass of ._(1)^(1)H=1.007825u , mass of ._(2)^(4)He=4.00260 u and 1u=931.5 MeV Neglect the mass of positron (._(+1)^(0)e) .

If mass of proton =1.007825 u, mass of neutron =1.008665 u, and mass of ._(3)Li^(7) is 7.01599u, and 1a.m.u. =931MeV, what is BE/nucleon of ._(3)Li^(7) .

A deuterium nucleus at rest absorbs a Gamma ray photon of energy 2.21 MeV and splits into a proton and a neutron. The neutron was found to be at rest after the disintegration. Calculate the mass of proton if it is known that mass of deuterium and hydrogen atom is 2.014740u and 1.008145u respectively. [1 u=931 MeV//c^(2)]

Find the amount of energy produced in joules due to fission of 1 gram of uranium assuming that 0.1 percent of mass is transformed into energy. Take 1amu= 1.66xx10^(-27)kg=931.5MeV Mass of uranium =235amu. Avogadro number = 6.02xx10^(23)

Assertion: The standard unit for expressing the mass of atoms is a.m.u. Reason: a.m.u. stands for mass of 1 atom of carbon.

The isotope _(5)^(12) B having a mass 12.014 u undergoes beta - decay to _(6)^(12) C _(6)^(12) C has an excited state of the nucleus ( _(6)^(12) C ^(**) at 4.041 MeV above its ground state if _(5)^(12)E decay to _(6)^(12) C ^(**) , the maximum kinetic energy of the beta - particle in unit of MeV is (1 u = 931.5MeV//c^(2) where is the speed of light in vacume ) .

A nucleus of radium (._(88)Ra^(226)) decays to ._(86)Rn^(222) by emisson of alpha- particle (._(2)He^(4)) of energy 4.8MeV . If meass of ._(86)Rn^(222)=222.0 a.m.u mass of ._(2)He^(4) is 4.003 a.m.u. and mass of ._(88)Ra^(226) is 226.00826 a.m.u., then calculate the recoil energy of the daughter nucleus. Take 1 a.m.u. =931MeV