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The neutron separation energy is defined...

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separation energy of the nuclei `._(20)Ca^(41)` and `._(13)Al^(27)` from the following data : `m(._20Ca^(40))=39.962591u` and `m(._(20)Ca^(41))=40.962278u`
`m(._(13)Al^(26))=25.986895u` and `m(._(13)Al^(27))=26.981541u`

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The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separartion energy of the nuclei ._(20)Ca^(41) and ._(13)Al^(27) form the following data : m(._20Ca^(40))=39.962591u and m(._(20)Ca^(41))=40.962278u m(._(13)Al^(26))=25.986895u and m(._(13)Al^(27))=26.981541u

Calculate the binding energy per nucleon of ._(20)Ca^(40) nucleus. Mass of (._(20)Ca^(40)) = 39.962591 am u .

Obtain the binding energy of the nuclei ._26Fe^(56) and ._83Bi^(209) in units of MeV form the following data: m(._26Fe^(56))=55.934939a.m.u. , m=(._83Bi^(209))=208.980388 a m u . Which nucleus has greater binding energy per nucleon? Take 1a.m.u 931.5MeV

What is the minimum photon energy required to remove the least bound neutron of ._(20)^(40)Ca and ._(18)^(40)Ar . The nesessary atomic masses (in mu ) are given below: {:(M(.^(40)Ca)=39.962591 u),(M(.^(39)Ca)=38.970719 u),(M(.^(40)Ar)=39.962383 ),(M(.^(39)Ar)=38.964314 u),(" "m_n=1.008665 u):}

Find energy required to break an aluminium nucleus into its constituent nucleons ( m_n = 1.00867 u , m_p = 1.00783 u , m_Al = 26.98154 u )

Calculate the energy required to remove the least tightly neutron form .^20(Ca^(40)) . Given that Mass of .^20(Ca^(40)) = 39.962589 amu Mass of .^20(Ca^(39)) = 38.970691 amu Mass of neutron = 1.008665 amu

(a) Find the energy needed to remove a neutron from the nucleus of the calcium isotope ._(20)^(42)Ca . (b) Find the energy needed to remove a proton from this nucleus. (c ) Why are these energies different? Mass of . _(20)^(40)Ca =40.962278u , mass of proton =1.007825 u .

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