A metre long narrow bore held horizontally (and close at one end) contains a `76` cm long mercury thread, which traps a `15` cm column of air. What happens if the tube is held vertically with the open end at the bottom?

A 10.0 cm column of air is trapped by a column of Hg 4.00 cm long in capillary tube of uniform bore when the tube is held horizontally in a room at 1 atm. Length of the air column when the tube is held vertically with the open end up is

If above tube is held vertical with open end upward then find the length of air column (in cm).

A long horizontal glass capillary tube open at both ends contains a mercury thread 1 m long at 0^@C . Find the length of the mercury thread, as read on this scale, at 100^@C .

A thin tube of uniform cross-section is sealed at both ends. It lies horizontally, the middle 5 cm containing mercury and the two equal end containing air at the same pressure P. When the tube is held at an angle of 60^@ with the vetical direction, the length of the air column above and below the mercury column are 46 cm and 44.5 cm respectively. Calculate the pressure P in centimeters of mercury. (The temperature of the system is kept at 30^@C ).

A column of mercury of 10cm length is contained in the middle of a narrow horizontal 1m long tube which is closed at both the ends. Both the halves of the tube contain air at a pressure of 76 cm of mercury. By what distance will the column of mercury be displaced if the tube is held vertically?