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The volume of a gas at pressure 1.2 xx 1...

The volume of a gas at pressure `1.2 xx 10^(7) Nm^(-2)` and temperature `127^(@)C` is `2.0` litre. Find the number of molecules in the gas.

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To solve the problem of finding the number of molecules in a gas given its pressure, volume, and temperature, we can follow these steps: ### Step 1: Write down the given data - Pressure (P) = \(1.2 \times 10^7 \, \text{N/m}^2\) - Temperature (T) = \(127^\circ C\) - Volume (V) = \(2.0 \, \text{liters}\) ### Step 2: Convert the temperature to Kelvin To convert Celsius to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] So, \[ T = 127 + 273 = 400 \, K \] ### Step 3: Convert the volume from liters to cubic meters 1 liter is equal to \(10^{-3}\) cubic meters. Therefore, \[ V = 2.0 \, \text{liters} = 2.0 \times 10^{-3} \, \text{m}^3 \] ### Step 4: Use the Ideal Gas Equation The Ideal Gas Equation is given by: \[ PV = nRT \] Where: - \(P\) = pressure - \(V\) = volume - \(n\) = number of moles - \(R\) = gas constant (\(8.314 \, \text{J/(mol K)}\)) - \(T\) = temperature in Kelvin ### Step 5: Rearrange the equation to solve for \(n\) \[ n = \frac{PV}{RT} \] ### Step 6: Substitute the values into the equation Substituting the known values: \[ n = \frac{(1.2 \times 10^7 \, \text{N/m}^2)(2.0 \times 10^{-3} \, \text{m}^3)}{(8.314 \, \text{J/(mol K)})(400 \, K)} \] ### Step 7: Calculate \(n\) Calculating the numerator: \[ 1.2 \times 10^7 \times 2.0 \times 10^{-3} = 2.4 \times 10^4 \] Calculating the denominator: \[ 8.314 \times 400 = 3325.6 \] Now substituting back: \[ n = \frac{2.4 \times 10^4}{3325.6} \approx 7.22 \, \text{moles} \] ### Step 8: Calculate the number of molecules To find the number of molecules, we use Avogadro's number, which is \(6.022 \times 10^{23} \, \text{molecules/mole}\): \[ \text{Number of molecules} = n \times N_A \] \[ = 7.22 \times 6.022 \times 10^{23} \] ### Step 9: Perform the final calculation Calculating the number of molecules: \[ = 7.22 \times 6.022 \approx 43.46 \times 10^{23} \approx 4.346 \times 10^{24} \, \text{molecules} \] ### Final Answer The number of molecules in the gas is approximately \(4.346 \times 10^{24}\). ---
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