Two metal plates form a parallel plate capacitor. The distance between the plates is d. A metal sheet of thickness d/2 and of the same area is indroduced between the plates. What is the ratio of the capacitances in the two cases?

Two metal plates form a parallel plate condenser. The distance between the plates in d. Now a metal plate of thickness d/2 and of same area is inserted completely between the plates, the capacitance

The capacitance of a parallel plate condenser with a separation of 4 mm between the plates is 7muF . If a mica sheet (K=6) of thickness 2 mm and of the same area is introduced betwenn the plates, its capacitance will be

The' distance between the plates of a parallel plate capacitor is d . A metal plate of thickness d//2 is placed between the plates. What will e its effect on the capacitance.

Two metal plates are separated by a distance d in a parallel plate condenser. A metal plate of thickness t and of the same area is inserted between the condenser plates. The value of capacitance increases by ….times.

The distance between the plates fo a parallel plate capacitor is d. A metal plate of thickness d//2 is placed between the plates, what will be the new capacity ?

Two identical metal plates separated by a distance 'd' form parallel plate capacitor (air gap) of capacitance C. A metal sheet of thickness (d/2) and same dimensions is inserted between the plates ,so that the air gap is separated into two equals parts. The new capacity of the system will be:

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

In a parallel plate capacitor, the distance between the plates is d and potential difference across the plate is V . Energy stored per unit volume between the plates of capacitor is