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A slab of material of dielectric constan...

A slab of material of dielectric constant K has the same area as the plates of a parallel capacitor, but has a thickness `((3)/(4) d)`,
where d is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates

Text Solution

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The correct Answer is:
`C=(4kappa)/(kappa+3)C_(0)`
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