2-methyl propane on oxidation with `KMnO_(4)` gives

Options

A. 2-methyl propane-2-ol
B. 2-methyl propan-1-ol
C. butane
D. butanol-1

Explanation

To solve the question of what product is formed when 2-methylpropane is oxidized with KMnO4, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 2-Methylpropane**:
- 2-methylpropane, also known as neopentane, has the following structure:
```
CH3
|
CH3-C-CH3
|
CH3
```
- This structure consists of a central carbon atom bonded to two methyl groups and two other carbon atoms.

2. **Understand the Oxidation Process**:
- KMnO4 (potassium permanganate) is a strong oxidizing agent. When it reacts with alkanes, it typically adds oxygen to the molecule and can convert secondary and tertiary alcohols into ketones or aldehydes.

3. **Determine the Type of Carbon Atoms**:
- In 2-methylpropane, the central carbon atom (C-2) is a tertiary carbon because it is bonded to three other carbon atoms. The other carbon atoms are primary.

4. **Predict the Reaction**:
- The oxidation will occur primarily at the tertiary carbon (C-2) due to its higher electron density. The reaction will involve the addition of an -OH group (hydroxyl group) to this carbon, replacing one of the hydrogen atoms.

5. **Draw the Product**:
- After oxidation, the product will have an -OH group on the second carbon:
```
CH3
|
CH3-C(OH)-CH3
|
CH3
```
- This compound is a tertiary alcohol.

6. **Name the Product**:
- The IUPAC name for this compound is 2-methylpropane-2-ol, indicating that the hydroxyl group is on the second carbon of the propane chain.

### Final Answer:
The product formed when 2-methylpropane is oxidized with KMnO4 is **2-methylpropane-2-ol**.

---