`(CH_(3))_(3)-C-MgCl` on reaction with `D_(2)O` produces

Options

A. `(CH_(3))_(3)CD`
B. `(CH_(3))_(3)COD`
C. `(CH_(3))_(3)CH`
D. `(CD_(3))_(3)COD`

Explanation

To solve the question regarding the reaction of `(CH₃)₃C-MgCl` with `D₂O`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Grignard Reagent**:
The compound `(CH₃)₃C-MgCl` is a Grignard reagent where `(CH₃)₃C` (tert-butyl group) is the organic part, and `MgCl` is the magnesium halide.

**Hint**: Recognize that Grignard reagents are typically of the form R-MgX, where R is an alkyl or aryl group and X is a halogen.

2. **Understand the Reaction with Water**:
Grignard reagents react with water (or in this case, heavy water `D₂O`) to produce hydrocarbons and magnesium hydroxide halides. The general reaction is:
\[ R-MgX + H₂O \rightarrow R-H + Mg(OH)X \]
Here, `R` represents the alkyl group.

**Hint**: Remember that Grignard reagents are highly reactive and will react with any source of protons.

3. **Substituting Heavy Water**:
When we use `D₂O` instead of regular water, the hydrogen (H) in the product will be replaced by deuterium (D). Thus, the reaction can be represented as:
\[ (CH₃)₃C-MgCl + D₂O \rightarrow (CH₃)₃C-D + Mg(OH)Cl \]

**Hint**: Keep in mind that deuterium is an isotope of hydrogen and will replace hydrogen in the product.

4. **Final Product**:
The final product of the reaction will be `(CH₃)₃C-D` (tert-butyl deuteride) along with magnesium hydroxide chloride as a byproduct.

**Hint**: Always check the stoichiometry of the reaction to ensure all reactants and products are accounted for.

### Conclusion:
The reaction of `(CH₃)₃C-MgCl` with `D₂O` produces `(CH₃)₃C-D` and `Mg(OH)Cl`.