The maximum number of carbon atoms in the expected products of the following reaction
`CH_(3)CH_(2)Br+CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)Broverset("Na/ether")to` Product

Answer

To determine the maximum number of carbon atoms in the expected products of the reaction between `CH₃CH₂Br` (ethyl bromide) and `CH₃-CH(CH₃)-CH₂Br` (isopropyl bromide) using sodium in ether (Wurtz reaction), we can follow these steps:

### Step 1: Identify the Reactants
The reactants are:
- Ethyl bromide: `CH₃CH₂Br`
- Isopropyl bromide: `CH₃-CH(CH₃)-CH₂Br`

### Step 2: Understand the Wurtz Reaction
The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal, leading to the formation of higher alkanes.

### Step 3: Determine Possible Coupling Products
1. **Ethyl bromide with itself**:
- `2 CH₃CH₂Br` → `CH₃-CH₂-CH₂-CH₃` (butane, C₄H₁₀)

2. **Isopropyl bromide with itself**:
- `2 CH₃-CH(CH₃)-CH₂Br` → `CH₃-CH(CH₃)-CH(CH₃)-CH₃` (2-methylbutane, C₅H₁₂)

3. **Ethyl bromide with isopropyl bromide**:
- `CH₃CH₂Br + CH₃-CH(CH₃)-CH₂Br` → `CH₃-CH₂-CH(CH₃)-CH₃` (pentane, C₅H₁₂)

### Step 4: Count the Carbon Atoms in Each Product
- Butane (from ethyl bromide with itself): 4 carbon atoms
- 2-Methylbutane (from isopropyl bromide with itself): 5 carbon atoms
- Pentane (from ethyl bromide with isopropyl bromide): 5 carbon atoms

### Step 5: Identify the Maximum Number of Carbon Atoms
The maximum number of carbon atoms in the products formed from these reactions is:
- The largest product is from the coupling of two isopropyl bromides, which gives us **8 carbon atoms** (from `2 CH₃-CH(CH₃)-CH₂Br`).

### Conclusion
The maximum number of carbon atoms in the expected products of the reaction is **8**.

---