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In SiF(6)^(-2) because of small size of ...

In `SiF_(6)^(-2)` because of small size of F

A

`SiF_(6)^(-2)` because of small size of F

B

`SiF_(6)^(-2)` because of large size of F

C

`SiCl_(6)^(-2)` because of small size of Cl

D

`SiCl_(6)^(-2)` because of large size of Cl

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Assertion: SiF_(6)^(2-) is known but SiCl_(6)^(2-) is not. Reason: Size of fluorine is small and its lone pair of electrons intersects with d-orbitals of Si strongly.

Assertion (R) SF_(6) is known but SCl_(6) is not. Reason (R) Due to small size of F.

In H_(2)SiF_(6) the covalency of silicon is

Statement-I: SiF_(6)^(-2) is known but SiCl_(6)^(-2) in not known Statement-II: Interaction of 'F' lone pair electrons with 'Si' is stronger than that of chlorine and due to smaller size of 'F' steric repulsion will bel less.

Statement-1: Fluorine has less electron affinity than chlorine. Statement-2 : Due to small size, more electron-electron repulsions are observed in F.

Statement-1:Beryllium does not form peroxide because Statement-2: Be^(2+) ion being of very small size cannot form a stable lattice with larger peroxide ion.

NARAYNA-14TH GROUP ELEMENTS-Level - V Single Answer Type
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  3. In SiF(6)^(-2) because of small size of F

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