In `C_(60)` 'x' number of 6 membered rings are present and 'y' number of 5 membered rings are possible then the difference of `x " & " y` is/are

Answer

To solve the problem, we need to determine the number of 6-membered rings (denoted as 'x') and the number of 5-membered rings (denoted as 'y') present in the structure of C60 (Buckminster Fullerene). Then, we will find the difference between these two values.

### Step-by-Step Solution:

1. **Identify the Structure of C60**:
- C60, also known as Buckminster Fullerene or Bucky Ball, is a molecular structure made up of carbon atoms arranged in a spherical shape.

2. **Count the Number of 5-Membered Rings**:
- In the structure of C60, there are 12 pentagonal (5-membered) rings. Therefore, we can denote this as:
\[ y = 12 \]

3. **Count the Number of 6-Membered Rings**:
- Additionally, C60 contains 20 hexagonal (6-membered) rings. We can denote this as:
\[ x = 20 \]

4. **Calculate the Difference Between x and y**:
- We need to find the difference between the number of 6-membered rings and the number of 5-membered rings:
\[ \text{Difference} = x - y = 20 - 12 \]

5. **Final Calculation**:
- Performing the subtraction gives us:
\[ \text{Difference} = 8 \]

### Conclusion:
The difference between the number of 6-membered rings (x) and the number of 5-membered rings (y) in C60 is:
\[ \text{Difference} = 8 \]