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The b.p of CF(4) is almost half that of ...

The b.p of `CF_(4)` is almost half that of `SiF_(4)` while the difference in b.p of `C Cl_(4) " and " SiCl_(4)` is little. This is because

A

the negative charge on fluorine cause greater repulsion between neighbouring molecules in `CF_(4)` where as it is less in `SiF_(4)` due to back bonding form `F rarr Si`

B

in `SiCl_(4)` inter-molecular repulsions are more due to the negative charge chlorine as `pi` back bonding formed `Cl rarr Si` is

C

`C Cl` bonds in `C Cl_(4)` are less polar then `Si - Cl` bond in `SiCl_(4)`

D

All are correct

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The correct Answer is:
D
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