How does the capacitive reactance depend on frequency at hertz to the study at ?

Explanation

current leads the applied voltage by `(pi)/(2)` in a capacitive circuit.
This is the resistance offered by the capacitor, called capacitive reactance `(X_(c)).` It measured in ohm.
`X_(c)=(1)/(omegaC)`
The capacitve reactance `(X_(c))` varies inversely as the frequency. For a steady current, F = 0.
`thereforeX_(c)=(1)/(omegaC)-(1)/(2pifC)=(1)/(0)=oo`
Thus a capacitive circuit offers infinie resistance to the steady current.