There are `n AM's` between `1 & 31` such that `7th` mean `: (n-1)th` mean`= 5:9`, then find the value of` n`

There are nAM's between 1&31 such that 7 th mean :(n-1)th mean =5:9, then find the value of n

There are n AM's between 1&31 such that 7thmean: (n-1) thmean =5:9, then find the value of n .

There are 'n' A.M.'s between 2 and 41. The ratio of 4th and (n - 1)th mean is 2 : 5, find the value of n.

There are n AM's between 3 and 54.Such that the 8th mean and (n-2) th mean is 3 ratio 5. Find n.

If n arithmetic means xare inserted between 1 and 31 such that the 7^(th) mean: the (n+1)^(th) mean =5:9 then prove that n=14

There are n A.M.s between 3 and 17. The ratio of the last mean to the first mean is 3:1. Find the value of n.

If n arithmetic means are inserted between 1 and 31 such that the ratio of the first mean nd nth mean is 3:29 then the value of n is 10 b.12 c.13 d.14