A solution curve of the differential equation `(x^2+xy+4x+2y+4)((dy)/(dx))-y^2=0` passes through the point `(1,3)` Then the solution curve is

The solution curve of the differential equation, (1+e^(-x))(1+y^(2))(dy)/(dx)=y^(2) , which passes through the point (0,1), is:

The solution of the differential equation (2x-4y+3)(dy)/(dx)+(x-2y+1)=0 is

The solution of the differential equation (x^(2)y^(2)-1)dy+2xy^(3)dx=0 is

Solution of the differential equation (dy)/(dx)=(4x-3y)/(3x-2y) is

Solution of the differential equation x((dy)/(dx))^(2)+2sqrt(xy)(dy)/(dx)+y=0 ,is

The solution of the differential equation x dx + y dy+ (x dy - y dx)/(x^(2)+y^(2))=0 is

The solution of the differential equation (2x^(2) +2 y^(2))dx- 4xy dy= 0 is

The solution of the differential equation (dy)/(dx) = (y^(2))/(xy-x^(2)) is

Solution of the differential equation (x^(2)+3xy+y^(2))dx-x^(2)dy=0 is

If the solution curve of the differential equation (2x-10y^(3))dy+ydx =0 , passes through the points (0, 1) and (2, beta) , then beta is a root of the equation :